To find the position of the image formed by the converging lens, we can use the lens equation:
1/f = 1/v - 1/u
Where:
- f is the focal length of the lens (15 cm)
- v is the distance of the image from the lens (unknown)
- u is the distance of the object from the lens (9 cm)
Substituting the given values into the equation:
1/15 = 1/v - 1/9
9v - 15u = uv
9v = uv + 15u
9v = u(v + 15)
v = u(v + 15)/9
Now, we can substitute the given values into the equation:
v = (9)(9 + 15)/9
v = (9)(24)/9
v = 24 cm
So, the distance of the image from the lens is 24 cm.
To find the magnification, we can use the formula:
magnification = -v/u
Using the given values:
magnification = -24/9
magnification = -8/3
So, the magnification of the image formed by the lens is -8/3.
A converging lens of
15cm focal length forms an image of an
object placed 9 cm from it. What is its
position and magnification?
1 answer