If the base has sides x, and the height is h, then the area is
x^2 + 4xh = 200
so, h = (200-x^2)/(4x) = 50/x - x/4
Now the volume is
v = x^2 h = x^2 (50/x - x/4) = 50x - x^3/4
Now just find where dv/dx = 0 for maximum volume.
Post your work if you get stuck
A container with a square base, vertical sides, and open top is to be made from 200ft^2 of material. Find the dimensions (length of base and the height) of the container with greatest volume. If appropriate, leave your answer in radical form and enter all fractions in lowest terms.
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