Ask a New Question

A container of gas is at a pressure of 1.3x10^5 Pa and a volume of 6.0m^3. How much work is done by the gas if it expands at constant pressure to twice its initial volume? Please help ;_;

1 answer

W = P(V2 - V1)
W = 1.3x10^5 (2x6 - 6 )
W = 780000 J

Ask a New Question or answer this question.

Similar Questions

sealed metal container can withstand a pressure difference of 0.630 . The container initially is filled with an ideal gas at 12
1. 1 answer
1. If 22.5 L of nitrogen at 748 mm Hg are compressed to 725 mm Hg at constant temperature. What is the new volume?2. A gas with
1. 5 answers
a flexible container at initial volume of 6.13 L contains 9.51 mol of gas. More gas is then added to the container until it
1. 1 answer
A container of gas has a volume of 3.5 L and a pressure of 0.8 atm. Assuming the temperature remains constant, what volume of
1. 1 answer

more similar questions