A container holds 2.2 mol of gas. The total average kinetic energy of the gas molecules in the container is equal to the kinetic energy of a 7.7x10-3 kg bullet with a speed of 650 m/s. What is the Kelvin temperature of the gas?

Answer 1

υ=2.2 mol, N₀=6.022•10²³ mol⁻¹,
k=1.38•10⁻²³ J/K

KE(ave) = υ•N₀•3kT/2
KE(bullet)=mv²/2
υ• N₀•3kT/2= mv²/2
T= mv²/3k• υ• N₀=
=7.7•10⁻³•650²/3• 1.38•10⁻²³•2.2•6.022•10²³=287 K

Answer 2

formula to use is:

T= (mv^2)/u No 3k