A container contains 15 liters af water at 96 celsius. A 1 kg of ice cube at -20 celsius is dropped into the water. No heat is lost to the surroundings. What will the final mixing temperature be?

1 answer

I do not remember heats of fusion and specific heats of ice and water, look them up
assuming all ice melts and water does not freeze:
15 liters = 15 kg of water

ice warms , heat in = (sh ice)(20)(1kg)
ice melts, heat in = (Hfusion)(1 kg)
ice water warms, heat in = (sh water) (T)(1 kg)
then
water cools, heat out = (sh water)(96-T)(15)
so if heat out = heat in
(sh water)(96-T)(15) = (sh ice)(20)(1kg) +(Hfusion)(1 kg)+ (sh water) (T)(1 kg)
s