A consultant traveled 7 hours to attend a meeting. The return trip took only 6 hours because the speed was 10 miles per hour faster. What was the consultant's speed each way?
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A train leaves town A for town B, traveling at 35 mi/h. At the same time, a second train leaves town B for town A at 45 mi/h. If the two towns are 320 mi apart, how long will it take for the two trains to meet?
A common mistake is in the equation below:
Write a clear explanation of what error has been made and what could be done to avoid the mistake. (Do not solve the equation.)
A consultant traveled 7 hours to attend a meeting. The return trip took only 6 hours because the speed was 10 miles per hour faster. What was the consultant's speed each way?
Using V = D/T
D = 7Vo = 6(Vo + 10) where Vo = the spped out.
Solve for Vo.
Vb = the speed back = Vo + 10.
A train leaves town A for town B, traveling at 35 mi/h. At the same time, a second train leaves town B for town A at 45 mi/h. If the two towns are 320 mi apart, how long will it take for the two trains to meet?
You know how fast the two trains are approaching one another, V-approach.
You know how far apart they are at the start, D-apart.
Apply V = D/T again to solve for T.
2 answers