A construction worker attempts to lift a uniform beam off the floor and raise it to a vertical position. The beam is 2.50m long and weighs 500N. At a certain instant the worker holds the beam momentarily at rest with one end at distance d=1.50m above the floor by exerting a force P on the beam, perpendicular to the beam. What is the magnitude P?
3 answers
It depends on where he is holding the beam, you did not state that.
He's pushing on it at the end that's not on the floor.
T= FpL- Wb(l/2)sin(53)
Fp = {Wb(l/2)sin(53)}/l
put the value,
Fp = 200 N
Fp = {Wb(l/2)sin(53)}/l
put the value,
Fp = 200 N
1 answer