The answer depends upon whether the "net applied force", which I will call F', includes the weight, W. I will assume that it does not. F' -W is the true net force, including weight.
Work done accelerating the stone is
F*x = (F' - W)*x = (385-28)* 2.0 = 714 Joules. That will equal the kinetic energy at release. Set it equal to
Work = M g h = Weight* h to compute the additional distance that it rises, h.
A constant net force of 385 N is applied upward to a stone that weighs 28 N. The upward force is applied through a distance of 2.0 m, and the stone is then released. To what height, from the point of release, will the stone rise?
what formulas?
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