accel = force / mass = 32 / 20 = 1.6 m/s^2
(9.0 m/s - 4.0 m/s) / 1.6 m/s^2 = ? s
A constant net force of 20 N is applied to a 32 kg car, causing it to speed up from 4.0 to 9.0 m/s. How long is the force applied?A constant net force of 20 N is applied to a 32 kg car, causing it to speed up from 4.0 to 9.0 m/s. How long is the force applied?
3 answers
F = M*a.
20 = 32a,
a = 0.625 m/s^2.
V = Vo + a*t.
9 = 4 + 0.625t,
t = ?.
20 = 32a,
a = 0.625 m/s^2.
V = Vo + a*t.
9 = 4 + 0.625t,
t = ?.
oops...got the fraction inverted
1 answer