Initial KE + work done=FinalKE
FinalKE-InitialKE=work done
1/2 m (6^2-4^2)=work done
A constant horizontal force of magnitude 18.0 N pushes a block of mass 2.00 kg along
a rough horizontal surface for a distance of 2.00 m. During this operation the speed
of the block changed from 4.00 m/s to 6.00 m/s. What work was done on the block
by kinetic friction?
(a) 32 J (b) 16 J (c) 8 J (d) 4 J (e) 0 J
The Correct Answer is b) but I don't know how to get this.
Thanks for you help.
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