since v=at,
and F=ma,
1/11 the force means 11 times as long
A constant force is exerted on a cart that is initially at rest on a frictionless air track. The force acts for a short time interval and gives the cart a final speed. To reach the same speed
using a force that is 1/11 as big, the force must be exerted for a time interval that is ?
1 answer