A. Consider the motion of a projectile. It is fired at t= 0. Its initial speed is 12 m/s and its initial projection angle is 50◦ from the horizontal. The acceleration of gravity is 9.8 m/s^2. What is the maximum height,h, of its trajectory?

Question

A. Consider the motion of a projectile. It is fired at t= 0. Its initial speed is 12 m/s and its initial projection angle is 50◦ from the horizontal. The acceleration of gravity is 9.8 m/s^2. What is the maximum height,h, of its trajectory?
Answer in units of m.

B. Consider two cases, where the initial speed v0 is fixed. The initial angle for the first case is θ1 and the initial angle for the second case is θ2.
The ratio of the time of flights t1/t2 is given by?

TG · Answer

I can only help with A, but use the equation h=(V^2*sin^2(angle))/(2*g) For your particular question I got, 4.306 meters.