To analyze the genetic situation, let's determine the potential genotypes of the offspring produced by an Xx female (carrier of hemophilia) and an XY male (unaffected).
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The possible gametes from the Xx female are:
- X (unaffected)
- x (affected)
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The gametes from the XY male are:
- X (unaffected)
- Y (male)
Combining these, we can set up a Punnett square:
| | X (from male) | Y (from male) | |--------|----------------|----------------| | X (from female) | XX | XY | | x (from female) | Xx | xY |
From this Punnett square, we have the following possible offspring genotypes:
- XX (unaffected female)
- XY (unaffected male)
- Xx (carrier female, not affected)
- xY (affected male)
Now we can summarize the genotypes of the offspring:
- 1 XX (unaffected female)
- 1 XY (unaffected male)
- 1 Xx (carrier female, not affected)
- 1 xY (affected male)
Now to find the fractions:
- Out of a total of 4 possible offspring:
- The fraction with at least one affected chromosome (either Xx female or xY male) is 2 out of 4, or 1/2.
- The fraction likely to be affected by hemophilia (only the xY male) is 1 out of 4, or 1/4.
Therefore, the answer to the question is: 1/2 and 1/4.