sinα=R/L=0.3/1=0.3
α=17.45°
mv²/R=Tsinα …..(1)
mg=Tcosα …..(2)
Divide (1) by (2)
v²/Rg=tanα
v=sqrt(R•g•tanα)=
=sqrt(0.3•9.8•0.31)=0.27 m/s
ω=v/R=0.27/0.3=0.9 rad/s
f= ω/2π=0.9/2•3.14=0.14rev/s=8.6 rev/min
T=mg/cosα=0.6•9.8/0.95=6.16 N
A conical pendulum is formed by attaching a 0.60kg ball to a 1.0m -long string, then allowing the mass to move in a horizontal circle of radius 30cm.
1. What is the tension in the string
2. What is the ball's angular velocity in rpm?
1 answer
5 answers