To find the volume of the cone-shaped container, we can use the formula for the volume \( V \) of a cone:
\[ V = \frac{1}{3} \pi r^2 h \]
where \( r \) is the radius and \( h \) is the height.
Given:
- \( r = 4 \) feet
- \( h = 12 \) feet
Now, substituting the values into the formula:
\[ V = \frac{1}{3} \pi (4)^2 (12) \] \[ = \frac{1}{3} \pi (16)(12) \] \[ = \frac{1}{3} \pi (192) \] \[ = 64\pi \]
Using the approximation \( \pi \approx 3.14 \):
\[ V \approx 64 \times 3.14 \approx 200.96 \text{ cubic feet} \]
So, the volume of the cone-shaped container is approximately 200.96 cubic feet.
From the given options (1.603.19, 2.16.76, 3.201.06), it seems like there might be some formatting issues. The closest option is 3.201.06, which might be an indication of the volume rounded or presented incorrectly.
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