To find the volume of a cone-shaped container, we can use the formula for the volume of a cone:
\[ V = \frac{1}{3} \pi r^2 h \]
where \( V \) is the volume, \( r \) is the radius, and \( h \) is the height.
Given:
- Radius (\( r \)) = 4 feet
- Height (\( h \)) = 12 feet
- \( \pi \) = 3.14
Now, we can substitute these values into the formula:
\[ V = \frac{1}{3} \times 3.14 \times (4)^2 \times 12 \]
Calculating \( (4)^2 \):
\[ (4)^2 = 16 \]
Now, substitute that back into the equation:
\[ V = \frac{1}{3} \times 3.14 \times 16 \times 12 \]
Calculating \( 16 \times 12 \):
\[ 16 \times 12 = 192 \]
Now, substituting this into the equation gives:
\[ V = \frac{1}{3} \times 3.14 \times 192 \]
Calculating \( 3.14 \times 192 \):
\[ 3.14 \times 192 = 601.44 \]
Now, we divide by 3:
\[ V = \frac{601.44}{3} = 200.48 \]
Thus, the volume of the feed that the container can store is:
\[ \boxed{200.48} \text{ cubic feet} \]