F=ILBsinα
sinα=1
B=F/IL = 2.2/2•1.5 =0.73 T
A conductor of length 2m carrying a 1.5A current experiences a force of 2.2 N. What is the magnitude of the magnetic field that acts perpendicular to the flow of current in the conductor?
0.73 Tesla
6.60 Tesla
0.34 Tesla
0.61 Tesla
1 answer