A concrete block of mass 35kg is pulled along a horizontal floor with the aid of a rope inclined at an angle of 30 degrees to the horizontal. If the coefficient of the friction is 0.75. Calculate the force required to move the block over the floor

Answer 1

M*g = 35*9.8 = 343 N. = Wt. of block. = Normal force, Fn.
Fs = u*Fn = 0.75*343 = 257.3 N. = force of starting friction.

F*Cos30 - Fs = M*a.
F*Cos30 - 257.3 = 35*0.

n

Answer 2

It is a nice network and I would like to get more of my answer from this network

Answer 3

Love your network