A concert loudspeaker suspended high above the ground emits 35 W of sound power. A small

microphone with a 1.0 cm2
area is 50 m from the speaker.
a. What is the sound intensity at the position of the microphone?
b. How much sound energy impinges on the microphone each second?

1 answer

a. To calculate the sound intensity at the position of the microphone, we can use the formula:

Intensity = Power / Area

Given that the power emitted by the loudspeaker is 35 W and the area of the microphone is 1.0 cm^2 (or 0.0001 m^2), we can plug these values into the formula:

Intensity = 35 W / 0.0001 m^2
Intensity = 350000 W/m^2

Therefore, the sound intensity at the position of the microphone is 350000 W/m^2.

b. To calculate the amount of sound energy impinging on the microphone each second, we can use the formula:

Sound energy = Intensity * Area

Given that the intensity is 350000 W/m^2 and the area of the microphone is 0.0001 m^2, we can plug these values into the formula:

Sound energy = 350000 W/m^2 * 0.0001 m^2
Sound energy = 35 W

Therefore, 35 W of sound energy impinges on the microphone each second.