A concentration cell consists of two Sn/Sn2+ electrodes. The electrolyte in compartment A is 0.16 M Sn(NO3)2. The electrolyte in B is 0.86 M Sn(NO3)2.

Question

A concentration cell consists of two Sn/Sn2+ electrodes. The electrolyte in compartment A is 0.16 M Sn(NO3)2. The electrolyte in B is 0.86 M Sn(NO3)2. 
Which electrode is the cathode?

What is the voltage of the cell? (Answer with two significant figures.)

DrBob222 · Answer

Ecell = Eocell - (0.05916/n)*log(dilute/concd) Eocell = 0 Substitute and solve for Ecell.