Let's solve the system of inequalities to find the possible combinations of computers and tablets the store can order.
From the first inequality:
875x + 235y ≤ 10000
we can rewrite it as:
875x ≤ 10000 - 235y
x ≤ (10000 - 235y) / 875
From the second inequality:
4x + 3y ≤ 45
we can rewrite it as:
4x ≤ 45 - 3y
x ≤ (45 - 3y) / 4
Now, we can plot the system of inequalities graphically and find the solution by finding the intersection point:
Graph:
x = (10000 - 235y) / 875
x = (45 - 3y) / 4
By solving these equations simultaneously, we get:
(10000 - 235y) / 875 = (45 - 3y) / 4
40000 - 940y = 2625 - 2625y
1680 = 675y
y = 2.4889
Substitute y back into either equation to solve for x:
x = (10000 - 235(2.4889)) / 875
x ≈ 8
Therefore, the combination of computers and tablets the store can order is approximately 8 computers and 2 tablets. So, the correct response is (8, 2).
A computer store is placing an order for computers and tablets. Each computer costs $875, and each tablet costs $235. The store can spend at most $10,000 for these computers and tablets. The computer store has a limited amount of space for displaying the new computers and tablets. Each computer takes up 4 square feet of space, and each tablet takes up 3 square feet of space. The store has only 45 square feet of display space available for the new computers and tablets. The system of inequalities shown can be used to determine possible combinations of computers, x, and tablets, y, the store can order.
875x+235≤10000
4x+3y≤45
Which combination of computers, x, and tablets, y, can the computer store order?
(1 point)
Responses
(10,2)
(7,9)
(8,4)
(5,9)
1 answer