A computer is reading data from a rotating CD-ROM. At a point that is 0.0316 m from the center of the disk, the centripetal acceleration is 282 m/s2. What is the centripetal acceleration at a point that is 0.0636 m from the center of the disc?

Answer 1

a₁= ω²R₁
a₂=ω²R₂

a₁/a₂ = R₁/R₂

a₂=a₁R₂/R₁=
=282•0.0636/0.0316 =567.6 m/s²