Take a 100 g sample. That gives you
39.97 g C
13.4 g H
46.62 g N
Convert to mols.
39.97/12 = mols C
13.41/1 = mols H
46.62/14 = mols N.
Now find the ratio of the elements to each other with the smallest being 1.00. The easy way to do that is to divide the smallest number by itself, then divide the other numbers by that same small number.
Post your work if you get stuck.
A compound with the percent composition shown below has a molar mass of 60.10g/mol. Find its molecular formula:
C, 39.97%
H, 13.41%
N, 46.62%
4 answers
Sorry for the intrusion, chemistry: timecode 6:44 I gave K one of your previous answers but it didn't suffice...
C H N
MASS 39.97g 13.41g 46.62
#mol 3.33 13.41 3.33
ratio 1 4 1
empirical formular CH4N
empirical mass 30
(CH4N)2=C2H8N2
THUS THE MOLECULAR FORMULA
MASS 39.97g 13.41g 46.62
#mol 3.33 13.41 3.33
ratio 1 4 1
empirical formular CH4N
empirical mass 30
(CH4N)2=C2H8N2
THUS THE MOLECULAR FORMULA
What is the empirical formula of 54.5% carbon 9.09% hydrogen and 36.4% oxygen
3 answers