A compound has the empirical formula CHCl. A 256 mL flask, at 373 K and 750. torr, contains 0.800 g of the gaseous compound. Give the molecular formula.

Answer 1

Use PV = nRT and solve for n.
Then n = grams/molar mass
Solve for molar mass.
Divide molar mass/empirical mass and round to a whole number which I will call x. Then (CHCl)x will be the molecular formula.