OK there is quite good routine way to do these....
C H O
48.65% 8.11% 43.24%
if we had 100 g
48.65g 8.11g 43.24g
so number of moles of each is
48.65/12 8.11/1 43.24/16
4.05 8.11 2.70
divide by smallest
1.5 3.0 1
or
3 6 2
so the empirical formula is
C3H6O2
a compound contains only c,h and o. c=48.65% and h=8.11%.a)calculate its emperical formula
1 answer
1 answer