A competitive cliff-diver jumps from a height of 75 feet. Find the number of feet the diver is above the ocean in 2 seconds. Evaluate for t=2

by using the formula 75−16t2
, where t
is time in seconds.(1 point)
s
Remaining Attempts : 3
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1 answer

To find the height of the cliff-diver above the ocean after 2 seconds, we can use the given formula:

\[ s(t) = 75 - 16t^2 \]

where \( s(t) \) is the height above the ocean in feet and \( t \) is the time in seconds.

Let's evaluate \( s(2) \):

  1. Substitute \( t = 2 \) into the formula:

\[ s(2) = 75 - 16(2^2) \]

  1. Calculate \( 2^2 \):

\[ 2^2 = 4 \]

  1. Now substitute that value back into the formula:

\[ s(2) = 75 - 16(4) \]

  1. Calculate \( 16 \times 4 \):

\[ 16 \times 4 = 64 \]

  1. Now substitute that value back into the formula:

\[ s(2) = 75 - 64 \]

  1. Perform the subtraction:

\[ s(2) = 11 \]

So, the diver is 11 feet above the ocean after 2 seconds.