a company sells one one of its product at rs.128 per unit in one year.Its cost function is given by X=0.01x^2+8x+7,where x represents the number of units.What will be the maximum profit of the company in nearest thousand rupee?

Answer 1

profit = income - cost
p(x) = 128x - (0.01x^2+8x+7) = -0.01x^2 + 120x - 7
Now just find the vertex in the usual way.