Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion in the smaller area (.23) and its Z score. Use the equation below.
Z = (score-mean)/SD
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 121.2-cm and a standard deviation of 1.8-cm.
Suppose a rod is chosen at random from all the rods produced by the company. There is a 23% probability that the rod is longer than:
Enter your answer as a number accurate to 1 decimal place. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
1 answer