Let's assume the number of cars sold by Dealership A is c and the number of trucks sold by Dealership A is t.
According to the information given, Dealership A sells a total of 164 cars and trucks, so we can write the equation:
c + t = 164 ----(1)
Dealership B sells twice as many cars as Dealership A, so the number of cars sold by Dealership B is 2c. Dealership B sells half as many trucks as Dealership A, so the number of trucks sold by Dealership B is (1/2)t. The total number of cars and trucks sold by Dealership B is given as 229, so we can write the equation:
2c + (1/2)t = 229 ----(2)
Now, we can solve these two equations simultaneously to find the values of c and t.
From equation (1), we can express c in terms of t:
c = 164 - t
Substituting this value of c into equation (2):
2(164 - t) + (1/2)t = 229
328 - 2t + (1/2)t = 229
328 - 229 = (3/2)t
99 = (3/2)t
Multiplying both sides by 2/3:
t = (2/3) * 99
t = 66
Substituting this value of t into equation (1):
c + 66 = 164
c = 164 - 66
c = 98
Therefore, Dealership A sells 98 cars and 66 trucks, while Dealership B sells 2 * 98 = 196 cars and (1/2) * 66 = 33 trucks.
A company owns two dealerships, both of which sells cars and trucks. Dealerships A sell a total 164, cars and trucks. Dealerships B sells twice as many car and half as many trucks as dealerships A, and sells a total of 229 cars and trucks
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