A company owns two dealerships, both of which sell cars and trucks. Dealership A sells a total of 225 cars and trucks. Dealership B sells twice as many cars and half as many trucks as the Dealership A and sells a total of 300 cars and trucks. How many cars did Dealership A sell? Given the fact that Dealership B sold half as many trucks as Dealership A, how many trucks did Dealership B sell?

Answer 1

Let's call the number of cars Dealership A sold x.
Dealership B sold twice as many cars as Dealership A, so Dealership B sold 2x cars.
Dealership A and B together sold a total of 225 +300 = <<225+300=525>>525 cars and trucks.
The total number of trucks Dealerships A and B sold is 525 - x - 2x = 525 - 3x.
Dealership B sold half as many trucks as Dealership A, so 525 -3x = x/2.
That means Dealership A sold 2(525-3x) = 1050-6x cars.
This means that 1050 - 6x = x.
Thus 1050 = 7x
Thus the x = 150 cars.
Thus Dealership A sold 150 cars and Dealership B sold 2(150)= <<2*150=300>>300 cars.
Dealership B sold half as many trucks as Dealership A, so Dealership B sold 150/2 = <<150/2=75>>75 trucks. Answer: \boxed{75}.