Let's assume that the number of cars sold by Dealership A is c, and the number of trucks sold is t.
We know that c + t = 225.
Dealership B sold twice as many cars as Dealership A, so the number of cars sold by Dealership B is 2c.
Dealership B sold half as many trucks as Dealership A, so the number of trucks sold by Dealership B is t/2.
The total number of cars and trucks sold by Dealership B is 2c + t/2 = 300.
Combining these two equations, we get 2c + t/2 = 300
Multiplying both sides of the equation by 2 gives 4c + t = 600.
Subtracting c + t = 225 from the equation 4c + t = 600, we get 3c = 375.
Dividing both sides of the equation by 3 gives c = 125.
Putting this value in c + t = 225, we get 125 + t = 225
Subtracting 125 from both sides of the equation gives t = 225 - 125 = <<225-125=100>>100.
So, Dealership B sold 100 trucks. Answer: \boxed{100}.
A company owns two dealerships, both of which sell cars and trucks. Dealership A sells a total of 225 cars and trucks. Dealership B sells twice as many cars and half as many trucks as the Dealership A, and sells a total of 300 cars and trucks. Given the fact that Dealership B sold half as many trucks as Dealership A, how many trucks did Dealership B sell?
1 answer