A company owns two dealerships, both of which sell cars and trucks. The first dealership sells a total of 164 cars and trucks. The second dealership sells twice as many cars and half as many trucks as the first dealership, and sells a total of 229 cars and trucks.

An equation for the total cars and trucks for dealership A:

An equation for the total cars and trucks for dealership B:

How many cars did dealership A sell?

How many trucks did the dealership B sell

1 answer

Equations:

A = number of cars and trucks sold at dealership A
B = number of cars and trucks sold at dealership B
C = number of cars sold at dealership A

A = 164
B = (2C) + (0.5(164-C)) = 229

Simplifying the second equation:

B = 2C + 82

We can now solve for C by substituting the value of C into the second equation:

B = 2(73) + 82 = 228

Therefore, dealership A sold 73 cars and 91 trucks (164 - 73 = 91).

Dealership B sold 73 cars and 155 trucks (229 - 73 = 156, but we need to divide by 2 because they sold half as many trucks as dealership A, so 156/2 = 78, and 229 - 78 = 155).