First, let's find the radius of the original can:
The diameter is 3, so the radius is 1.5 cm.
Using the formula for the volume of a cylinder, we can find the value of p as follows:
9p = pi x (1.5)^2 x 4
9p = 7.065
p = 7.065/9
p ≈ 0.785
Now, we need to calculate the volume of the new can:
V = 1.25 x 9p
V = 11.3125p
Using the formula A=pi x radius squared x height, and plugging in the values we know:
11.3125p = pi x r^2 x 4
r^2 = 11.3125p / (4 x pi)
r^2 ≈ 0.897
r ≈ 0.947 cm (rounded to the nearest tenth)
Therefore, the radius of the new can is approximately 0.9 cm.
A company manufactures cylindrical cans. Each can has a volume of 9p cubic centimetres and a height of 4 centimetres. The diameter of the can is 3. use 3.14 as pi. The company plans to manufacture a can with a volume that is 25% larger than
the original can. What is the radius of the new can if the height remains the same?
Round your answer to the nearest tenth. Use the formula A=pi x radius squared x height
1 answer