A common solution used by EMTs for keeping VEINS from collapsing in accident victims is 5% (m/v) dextrose (C6H12O6) in water. calculate the molarity of 5 %(m/v) dextrose in water .

Answer 1

To calculate the molarity of 5% (m/v) dextrose in water, we need to first convert the percentage to grams per liter:

5% (m/v) = 5 grams per 100 mL

We need to convert 100 mL to liters:

100 mL = 0.1 L

So, the concentration of dextrose in water is 5 grams per 0.1 liter, or 50 grams per liter.

Next, we need to calculate the molecular weight of dextrose (C6H12O6):

C = 12.01 g/mol
H = 1.01 g/mol
O = 16.00 g/mol

The molecular weight of dextrose is:

(6 x 12.01) + (12 x 1.01) + (6 x 16.00) = 180.18 g/mol

Finally, we can calculate the molarity of dextrose in water:

Molarity = moles of solute / liters of solution

To find the moles of dextrose in 1 liter of solution, we divide the mass by the molecular weight:

50 g / 180.18 g/mol = 0.277 moles

So, the molarity of 5% (m/v) dextrose in water is:

0.277 moles / 1 liter = 0.277 M