Number of possible choices of 5 members from a total of 15
= C(15,5) = 3003
a) number of all teachers = C(10,5) = 252
so prob(5 teachers) = 252/3003 = 12/143
b) 3 teachers, and 2 students
prob = C(10,3) * C(5,2)/3003 = ....
c) not clear with the wording.
Is it exactly 3 teachers or exactly 4 teachers, or is the case of 3 teachers included in 4 teachers?
I will go with the "exactly".
prob = ( C(10,3)C(5,2) + C(10,4)C(5,1) )/3003 =
A committe of 5 members will be chosen from a group of 10 teachers and 5 students. What is the probability that the committee
will have
A) all teachers?
B) 3 teachers and 2 students?
C) 3 or 4 teachers?
1 answer