A commertially available sample of H2SO4 is 15% of H2SO4 by weight. Density=1.10g. Calculate-

Question

1. Molarity
2. Normality
3. Molality

Answer 1

Wonder who would offer that as a "sample"?

Molarity: grams/molmass*volumeInLiters
so if you had one liter of this stuff, you so assume 1 liter of this stuff, which is 1100g

.15*1100/98*1=165/98 Moles/liter

Normality= 2*molarity

Molality=.15*1100/98*1.1

Answer 2

I believe I see a typo here for molality.
grams H2SO4 = 1100*0.15 = 165 as stated.
mols H2SO4 = 0.15*100/98 as stated.
grams solution = 1100 g as stated
BUT g solvent = 1100-165 = 935g (0.935 kg) so
molality = 0.15*1100/0.935 kg solvent = ?

Answer 3

yes, my eyes are failing.