Part 1 of 2:
For sodium hypochlorite:
Weight = 1.2 g
Volume = 24 mL = 0.024 L
% = (Weight of sodium hypochlorite / Volume of bleach) * 100
% = (1.2 g / 0.024 L) * 100
% = 50%
Therefore, the concentration of sodium hypochlorite in the bleach is 50%.
Part 2 of 2:
For sodium hydroxide:
Weight = 0.0096 g
Volume = 24 mL = 0.024 L
% = (Weight of sodium hydroxide / Volume of bleach) * 100
% = (0.0096 g / 0.024 L) * 100
% = 0.04%
Therefore, the concentration of sodium hydroxide in the bleach is 0.04%.
Both concentrations have the correct number of significant figures - 2.
A commercial bleach contains 1.2 g of sodium hypochlorite and 0.0096 g of sodium hydroxide in each 24. -mL portion. Calculate the
concentration for each component. Be sure each of your answer entries has the correct number of significant figures.
Part 1 of 2
weight
volume
percent
%
weight
volume
sodium hypochlorite
10
X
Part 2 of 2
%
weight
volume
sodium hydroxide
write the correct significant figure for both
1 answer