number of nickels ---- x
number of dimes ----- x+10
number of quarters = 37-(x + x+10) = 27 - 2x
value of coins = 5x + 10(x+10) + 25(27-2x)
= 5x + 10x + 100 + 675 - 50x
= 775 - 35 x
A collection of thirty-seven coins consists of nickels, dimes and quarters. There are ten more dimes than nickels. Represent the value of all the coins using one variable.
1 answer