A collar of Styrofoam is made to insulate a pipe. Find its volume. The large radius R is to the outer rim. The small radius r is to the edge of the insulation. Use pi almost equals 3.14 .

r
​=
2 in.
R
​=
3 in.
h
​=
19 in.

1 answer

To find the volume of the Styrofoam collar that insulates the pipe, we can consider it as a cylindrical shell. The volume \( V \) of the cylindrical shell can be calculated by finding the volume of the outer cylinder and subtracting the volume of the inner cylinder (the pipe).

The formula for the volume \( V \) of a cylinder is given by:

\[ V = \pi r^2 h \]

Step 1: Calculate the volume of the outer cylinder (radius \( R \))

Given:

  • Outer radius \( R = 3 \) in.
  • Height \( h = 19 \) in.

\[ V_{\text{outer}} = \pi R^2 h = \pi (3)^2 (19) \]

Calculating this:

\[ V_{\text{outer}} = \pi \cdot 9 \cdot 19 = \pi \cdot 171 \]

Substituting \( \pi \approx 3.14 \):

\[ V_{\text{outer}} \approx 3.14 \cdot 171 \approx 536.94 , \text{in}^3 \]

Step 2: Calculate the volume of the inner cylinder (radius \( r \))

Given:

  • Inner radius \( r = 2 \) in.
  • Height \( h = 19 \) in.

\[ V_{\text{inner}} = \pi r^2 h = \pi (2)^2 (19) \]

Calculating this:

\[ V_{\text{inner}} = \pi \cdot 4 \cdot 19 = \pi \cdot 76 \]

Substituting \( \pi \approx 3.14 \):

\[ V_{\text{inner}} \approx 3.14 \cdot 76 \approx 238.64 , \text{in}^3 \]

Step 3: Calculate the volume of the collar

Now we subtract the volume of the inner cylinder from the volume of the outer cylinder:

\[ V_{\text{collar}} = V_{\text{outer}} - V_{\text{inner}} \approx 536.94 - 238.64 \approx 298.30 , \text{in}^3 \]

Conclusion

The volume of the Styrofoam collar is approximately:

\[ \boxed{298.30} , \text{in}^3 \]