V^2 = Vo^2 + 2ax
0 = ((10.5rad/s)(0.00685m))^2 + (2)(2.34rad/s^2)(0.00685m)(x)
x = 0.16137 meters
A coin with a diameter of 1.37 cm is dropped
on its edge onto a horizontal surface. It
starts rolling with an initial angular speed
of 10.5 rad/s and rolls in a straight line without
slipping.
If the rotation slows with an angular deceleration
of 2.34 rad/s
2
, how far does the coin
roll before coming to rest?
Answer in units of m.
1 answer
2 answers