A coin is placed 11.0 cm from the axis of a rotating turntable of variable speed. When the speed of the turntable is slowly increased, the coin remains fixed on the turntable until a rate of 31 rpm is reached, at which point the coin slides off. What is the coefficient of static friction between the coin and the turntable?

Question

bobpursley · Answer

forcefriction=mg*mu centripetalforce= mw^2r w= 31*2PI/60 in rad/sec set them equal, solve for mu.

Anonymous · Answer

wouldnt w be 2pir/period in s