A coin is biased such that a head is thrice as likely to occur as a tail. Find the probability distribution of heads and also find the mean and variance of the distribution when it is tossed 4 times.


P(head) + P(tail) = 1

P(head) = 3 P(tail)

Solving gives:

P(head) = 3/4

If we assign 1 to heads and a 0 to tail, then the mean value is 4P(head) = 3, the variance is 4P(head)(1-P(head)) =
3/4

A coin is biased such that a head is thrice as likely to occur as a tail. Find the probability distribution of heads and also find the mean and variance of the distribution when it is tossed 4 times

A coin is biased such that a head is thrice as likely to occur as a tail. Find the probability distribution of heads and also find the mean and variance of the distribution when it is tossed 4 times.

1 answer

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