The formula for the volume \( V \) of a cone is given by:
\[ V = \frac{1}{3} \pi r^2 h \]
where
- \( r \) is the radius of the base of the cone, and
- \( h \) is the height of the cone.
Given:
- \( r = 3 \) inches
- \( h = 7 \) inches
- \( \pi \approx 3.14 \)
Now, plug the values into the formula:
\[ V = \frac{1}{3} \times 3.14 \times (3^2) \times 7 \]
First, calculate \( r^2 \):
\[ r^2 = 3^2 = 9 \]
Now substitute \( r^2 \) back into the volume formula:
\[ V = \frac{1}{3} \times 3.14 \times 9 \times 7 \]
Next, calculate \( 9 \times 7 \):
\[ 9 \times 7 = 63 \]
So now the equation becomes:
\[ V = \frac{1}{3} \times 3.14 \times 63 \]
Now, calculate \( 3.14 \times 63 \):
\[ 3.14 \times 63 = 197.82 \]
Finally, calculate \( \frac{1}{3} \times 197.82 \):
\[ V = \frac{197.82}{3} \approx 65.94 \]
Therefore, the volume of the coffee grounds the container can hold is approximately:
\[ \boxed{65.94} \text{ cubic inches} \]
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