To find the volume of a cone-shaped container, we can use the formula:
\[ V = \frac{1}{3} \pi r^2 h \]
where \( V \) is the volume, \( r \) is the radius, and \( h \) is the height.
Given:
- Radius \( r = 3 \) inches
- Height \( h = 7 \) inches
- Using \( \pi \approx 3.14 \)
Substituting the values into the formula:
\[ V = \frac{1}{3} \times 3.14 \times (3)^2 \times 7 \]
Calculating \( (3)^2 \):
\[ (3)^2 = 9 \]
Now substituting back:
\[ V = \frac{1}{3} \times 3.14 \times 9 \times 7 \]
Calculating \( 9 \times 7 \):
\[ 9 \times 7 = 63 \]
Now substituting this in:
\[ V = \frac{1}{3} \times 3.14 \times 63 \]
Calculating \( 3.14 \times 63 \):
\[ 3.14 \times 63 = 197.82 \]
Now, completing the calculation with \(\frac{1}{3} \times 197.82\):
\[ V = \frac{197.82}{3} \approx 65.94 \]
Thus, the volume of coffee grounds the container can hold is approximately:
\[ \boxed{65.94} \text{ cubic inches} \]
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