A coefficient of kinetic friction, k , is needed to stop a car in a distance D on dry pavement with the wheels locked if the car starts from speed V_0.

What coefficient of kinetic friction (in terms of k ) is needed to stop this car in the same distance if it starts from an initial speed of 3V_0?

2 answers

9K
Correct. It varies as V^2. The force must increase by 9 times to dissipate nine times as much energy as "work done against friction" in the same distance.