Asked by Shaun
A coal power plant with 30% efficiency burns 10 million kilograms of coal a day. What is the power output of the plant and at what rate is thermal energy being discarded by the plant?
Answers
Answered by
bobpursley
8 kWh of heat can be generated from 1 kg of coal, approx.
so Power output here = .30*8kWh*10e6/1day
= .30*8kWh*10e6*24 hours=2.7e15 joules
so Power output here = .30*8kWh*10e6/1day
= .30*8kWh*10e6*24 hours=2.7e15 joules
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