A club with twelve members is to choose three officers: president, vice-president, and secretary- treasurer. If each office is to be held by one person and no person can hold more than one office, in how many ways can those offices be filled.
1 answer
There are 12 choices for the president. After one person is chosen, there are 11 choices for the vice-president, and after two people have been chosen, there are 10 choices for the secretary-treasurer. Multiplying these together, we find the answer is $12 \times 11 \times 10 = \boxed{1320}$.