A closed container has 2.04 ⋅ 1023 atoms of a gas. Each atom of the gas weighs 1.67 ⋅ 10−24 grams. Which of the following shows and explains the approximate total mass, in grams, of all the atoms of the gas in the container? (1 point)

0.34 grams, because (2.04 ⋅ 1.67) ⋅ (1023 ⋅ 10−24) = 3.4068 ⋅ 10−1

0.37 grams, because (2.04 + 1.67) ⋅ (1023 ⋅ 10−24) = 3.71 ⋅ 10−1

3.41 grams, because (2.04 ⋅ 1.67) ⋅ (1023 ⋅ 10−24) = 3.4068

3.71 grams, because (2.04 + 1.67) ⋅ (1023 ⋅ 10−24) = 3.71

1 answer

The mass of a single atom is given as 1.67 ⋅ 10^-24 grams. To find the total mass of all the atoms in the container, we multiply this value by the number of atoms, which is 2.04 ⋅ 10^23. Using scientific notation, the calculation would be:

(2.04 ⋅ 10^23) * (1.67 ⋅ 10^-24) = (2.04 * 1.67) * (10^23 * 10^-24) = 3.4068 * 10^-1

Therefore, the approximate total mass of all the atoms of the gas in the container is 0.34 grams.

The correct answer is:
0.34 grams, because (2.04 ⋅ 1.67) ⋅ (10^23 ⋅ 10^-24) = 3.4068 ⋅ 10^-1