Use a confidence interval formula for proportions.
CI99 = p + or - (2.58)(√pq/n)
...where √ = square root, p = x/n, q = 1 - p, and n = sample size.
Hint: x = 300, n = 375
I hope this will help get you started.
A clinical trial test a method designed to increase probability of conceiving a girl.In study 375 were born and 300 were girls Use sample data to construct 99%confidence interval of percentage girls born
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