Huh?
Sin(25)*187+(36*9.81) = 432.19
the clerk is pulling UP not down
-Sin(25)*187+(36*9.81) =274.1 = normal force down on floor
274.1 * .410 = 112
so
187 cos 25 - 112 = 36 a
A clerk moves a box of cans down an aisle by pulling on a strap attached to the box. The clerk pulls with a force of 187.0 N at an angle of 25.0◦ with the horizontal. The box has a mass of 36.0 kg, and the coefficient of kinetic
friction between the box and floor is 0.410. The acceleration due to gravity is 9.81 m/s^2
What is the acceleration of the box?
When i tried to solve for it i did:
Sin(25)*187+(36*9.81) = 432.19
0.410(432.19) = 177.198
187*COS(25)-177.198= -7.71819
A = -7.71819/36 = -0.214394
The answer i submitted was wrong. i wonder if it was because i got a negative number as the Kinetic Force. Please review and help solve this.
1 answer
1 answer